Optimal. Leaf size=126 \[ \frac{2}{3} \sqrt{\frac{11}{3}} \text{EllipticF}\left (\sin ^{-1}\left (\sqrt{\frac{3}{7}} \sqrt{1-2 x}\right ),\frac{35}{33}\right )+\frac{\sqrt{3 x+2} (5 x+3)^{3/2}}{\sqrt{1-2 x}}+\frac{10}{3} \sqrt{1-2 x} \sqrt{3 x+2} \sqrt{5 x+3}+\frac{133}{6} \sqrt{\frac{11}{3}} E\left (\sin ^{-1}\left (\sqrt{\frac{3}{7}} \sqrt{1-2 x}\right )|\frac{35}{33}\right ) \]
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Rubi [A] time = 0.0355012, antiderivative size = 126, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.179, Rules used = {97, 154, 158, 113, 119} \[ \frac{\sqrt{3 x+2} (5 x+3)^{3/2}}{\sqrt{1-2 x}}+\frac{10}{3} \sqrt{1-2 x} \sqrt{3 x+2} \sqrt{5 x+3}+\frac{2}{3} \sqrt{\frac{11}{3}} F\left (\sin ^{-1}\left (\sqrt{\frac{3}{7}} \sqrt{1-2 x}\right )|\frac{35}{33}\right )+\frac{133}{6} \sqrt{\frac{11}{3}} E\left (\sin ^{-1}\left (\sqrt{\frac{3}{7}} \sqrt{1-2 x}\right )|\frac{35}{33}\right ) \]
Antiderivative was successfully verified.
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Rule 97
Rule 154
Rule 158
Rule 113
Rule 119
Rubi steps
\begin{align*} \int \frac{\sqrt{2+3 x} (3+5 x)^{3/2}}{(1-2 x)^{3/2}} \, dx &=\frac{\sqrt{2+3 x} (3+5 x)^{3/2}}{\sqrt{1-2 x}}-\int \frac{\sqrt{3+5 x} \left (\frac{39}{2}+30 x\right )}{\sqrt{1-2 x} \sqrt{2+3 x}} \, dx\\ &=\frac{10}{3} \sqrt{1-2 x} \sqrt{2+3 x} \sqrt{3+5 x}+\frac{\sqrt{2+3 x} (3+5 x)^{3/2}}{\sqrt{1-2 x}}+\frac{1}{9} \int \frac{-\frac{1263}{2}-\frac{1995 x}{2}}{\sqrt{1-2 x} \sqrt{2+3 x} \sqrt{3+5 x}} \, dx\\ &=\frac{10}{3} \sqrt{1-2 x} \sqrt{2+3 x} \sqrt{3+5 x}+\frac{\sqrt{2+3 x} (3+5 x)^{3/2}}{\sqrt{1-2 x}}-\frac{11}{3} \int \frac{1}{\sqrt{1-2 x} \sqrt{2+3 x} \sqrt{3+5 x}} \, dx-\frac{133}{6} \int \frac{\sqrt{3+5 x}}{\sqrt{1-2 x} \sqrt{2+3 x}} \, dx\\ &=\frac{10}{3} \sqrt{1-2 x} \sqrt{2+3 x} \sqrt{3+5 x}+\frac{\sqrt{2+3 x} (3+5 x)^{3/2}}{\sqrt{1-2 x}}+\frac{133}{6} \sqrt{\frac{11}{3}} E\left (\sin ^{-1}\left (\sqrt{\frac{3}{7}} \sqrt{1-2 x}\right )|\frac{35}{33}\right )+\frac{2}{3} \sqrt{\frac{11}{3}} F\left (\sin ^{-1}\left (\sqrt{\frac{3}{7}} \sqrt{1-2 x}\right )|\frac{35}{33}\right )\\ \end{align*}
Mathematica [A] time = 0.152806, size = 105, normalized size = 0.83 \[ \frac{67 \sqrt{2-4 x} \text{EllipticF}\left (\sin ^{-1}\left (\sqrt{\frac{2}{11}} \sqrt{5 x+3}\right ),-\frac{33}{2}\right )+6 \sqrt{3 x+2} \sqrt{5 x+3} (19-5 x)-133 \sqrt{2-4 x} E\left (\sin ^{-1}\left (\sqrt{\frac{2}{11}} \sqrt{5 x+3}\right )|-\frac{33}{2}\right )}{18 \sqrt{1-2 x}} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.016, size = 140, normalized size = 1.1 \begin{align*} -{\frac{1}{540\,{x}^{3}+414\,{x}^{2}-126\,x-108}\sqrt{1-2\,x}\sqrt{2+3\,x}\sqrt{3+5\,x} \left ( 67\,\sqrt{2}\sqrt{3+5\,x}\sqrt{2+3\,x}\sqrt{1-2\,x}{\it EllipticF} \left ( 1/11\,\sqrt{66+110\,x},i/2\sqrt{66} \right ) -133\,\sqrt{2}\sqrt{3+5\,x}\sqrt{2+3\,x}\sqrt{1-2\,x}{\it EllipticE} \left ( 1/11\,\sqrt{66+110\,x},i/2\sqrt{66} \right ) -450\,{x}^{3}+1140\,{x}^{2}+1986\,x+684 \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (5 \, x + 3\right )}^{\frac{3}{2}} \sqrt{3 \, x + 2}}{{\left (-2 \, x + 1\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (5 \, x + 3\right )}^{\frac{3}{2}} \sqrt{3 \, x + 2} \sqrt{-2 \, x + 1}}{4 \, x^{2} - 4 \, x + 1}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (5 \, x + 3\right )}^{\frac{3}{2}} \sqrt{3 \, x + 2}}{{\left (-2 \, x + 1\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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